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Obtain the relation of voltage applied to a series LCR circuit. |
Answer» Solution :Below figure shows a series LCR circuyit connected to an AC source `.epsilon.`. Voltage of an AC source is `V = V_(m) sin OMEGA t `. Let q is the charge on the CAPACITOR and I the current at time t, `:. V = V_(L ) + V_(R ) + V_( C )` From Kirchhoff.s loop rule `L ( dI)/( dt) + IR + ( q )/( C ) = V ` From Kirchhoff.s loop rule `L (dI)/(dt) + IR + ( q)/( C ) = V ` where potential difference across the ends `= L (dI)/( dt )` potential difference across the ends of capacitor `= ( q )/( C )` and potential difference across the ends of resistance `= I_(R )`. |
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