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Obtain the resonant frequency omega_(r ) of a series jLCR circuit with L= 2.0 H, C = 32 muF and R = 10 Omega . What is the Q-value of this circuit ? |
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Answer» Solution :`omega_(r ) = omega_(0) = (1)/(sqrt(LC))` `:. omega_(r ) = ( 1)/( sqrt(2 XX 32 xx 10^(-6)))` `:. omega_(r ) = 125 (rad)/( s )` Q VALUE( or Q factor ) `= ( omega_(r ) L )/( R )` ` = ( 125 xx 2)/( 10)` ` = ( 1)/( 10) sqrt( ( 2) /( 32 xx 10^(-6)))` ` = (1)/(10) xx (1000)/( 4)` = 25 |
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