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InterviewSolution
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Obtain the resonant frequency omega_(r) of a series LCR circuit with L = 2.0 H. C = 32muF, and R=10Omega. What is the Q - value of this circuit? |
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Answer» Solution :`omega= (1)/(sqrt(LC))` `omega = (1)/(sqrt(2 xx 32 xx 10^(-6))` `omega = (1)/(8 xx 10^(-3))` `omega= 125 Hz` `Q = (1)/(R ) sqrt((L)/(C )` Substitution `= (omega L)/(R ) = (1)/(omega RC)` CALCULATION of Q = 25 |
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