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| 1. |
Obtainthe formulafor the electricfield due to a longthin wireofuniform linear charge density E without using gauss law |
| Answer» Solution :Considerthe conlductor with the holefilled up then the fieldjust oputside is`vecn` and is zero INSIDE view this field asto the rest of the chargedconductor inside the conductor these fieldsar equal and oppositeoutsidethey are equal both in mangitude and direction hence the field due to the RESTOF THECONDUCTORIS `(omega)/(2epsilon_(0))vecn` | |