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Of the following atoms, which one of the highest n/p ratio |
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Answer» `NE^(16)` `._(10)Ne^(16) RARR ._(n =6)^(p = 10) (n)/(p) = (6)/(10) = 0.6, ._(8)O^(16) rArr._(n=8)^(p=8) n//p = 1` `._(9)F^(16) rArr._(n =7)^(p =9)(n)/(p) = (7)/(9) = 0.778 ? , N^(16) rArr ._(n =9)^(p = 7)n//p = (9)/(7) = 1.2857` |
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