)olumeİ) 6,022 molecules of NH3ii) 0.1 M of SO2 – InterviewSolution

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1.

)olumeİ) 6,022 molecules of NH3ii) 0.1 M of SO2

Answer»

in 1 moles the volume of gas is 22.4 L

so. 1) 6.022× 10²³ molecules = 1 moles. so volume will be 22.4 L

2) 0.1 M SO2..Volume occupied by 1 mole of SO2= 22.4 LVolume occupied by 0.1 mole = 2.24 L

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