1.

On a railway track of radius of curvature 1600 m. If the distance between two trackes is 1.8 m, then the elevation of the outer track above the inner track will be(g=10m//s^(2))

Answer»

`0.450 m`
`0.0450 m`
`4.50 m`
`4.0 m`

SOLUTION :` TAN theta =(v^(2))/(rg) therefore (h)/(l)=(v^(2))/(rg)`
Where l is DISTANCE between TWO tracks.


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