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On a Saturday night, 20%of all drivers in U.S.A. are under theinfluence of alcohol. The probability that a drive under the influence ofalcohol will have an accident is 0.001. The probability that a sober drivewill have an accident is 0.00. if a car on a Saturday night smashed into atree, the probability that the driver was under the influence of alcohol is`3//7`b. `4//7`c. `5//7`d. `6//7`A. `3//7`B. `4//7`C. `5//7`D. `6//7` |
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Answer» Correct Answer - C A: car met with an accident `B_(1):` driver was alcoholic, `P(B_(1))=1//5` `B_(2):` driver was sober, `P(B_(2))=4//5` `P(A//B_(1))=0.001,P(A//B_(2))=0.0001` `P(B_(1)//A)((0.2)(0.001))/((0.2)(0.001)+(0.8)(0.0001))=5//7` |
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