On adding excess of `NH_(3)` solution to `CuSO_(4)` solution, the dark blue colour is due toA. `[Cu(CH_(3))_(4)]^(++)`B. `[Cu(NH_(3))_(2)]^(++)`C. `[Cu(NH_(3))]^(+)`D. None of the above

On adding excess of `NH_(3)` solution to `CuSO_(4)` solution, the dark

1.	On adding excess of `NH_(3)` solution to `CuSO_(4)` solution, the dark blue colour is due toA. `[Cu(CH_(3))_(4)]^(++)`B. `[Cu(NH_(3))_(2)]^(++)`C. `[Cu(NH_(3))]^(+)`D. None of the above
Answer» Correct Answer - A `CuSO_(4) + 4NH_(3) = [Cu(NH_(3))_(4)]^(+ +) SO_(4)^(- -)`

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On adding excess of `NH_(3)` solution to `CuSO_(4)` solution, the dark blue colour is due toA. `[Cu(CH_(3))_(4)]^(++)`B. `[Cu(NH_(3))_(2)]^(++)`C. `[Cu(NH_(3))]^(+)`D. None of the above

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