1.

On adding which of the following the pH of 20 mL of 0.1 N HCl will not alter ?

Answer»

1 mL of 1 N HCl
20 mL of DISTILLED WATER
1 mL of 0.1 N NaOH
500 mL of HCl of pH = 1.

Solution :pH of 20 mL of `0.1 N HCl= -log [H^(+)]`
`=-log (0.1)=1`
The given solution has pH = 1
`therefore` When 500 mL of HCl of pH = 1 is added to the given solution, pH REMAINS same.


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