1.

On addition of increasing amount of AgNO_(3)(g)to 0.1 M each of NaCl and NaBr in a solution, what % of Br^(-)ion gets precipitated when Cl^(-)ion starts precipitating? Given: K_(sp)(AgCl) = 1.0 xx 10^(-10), K_(sp) (AgBr) = 1 xx 10^(-13).

Answer»


SOLUTION :`[AG^(+)]` required for commencement of percipitation of AgCl `=(K_(sp)(AgCl))/([Cl^(-)])= (1.0 xx 10^(-10))/0.1`
`=1.0 xx 10^(-9)` M
`[Br^(-)]` remaining at this stage
% of `Br^(-)` remaining unpredicted
% of `Br^(-)` precipitated =100-0.1 = 99.9


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