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On analysing an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the sample? |
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Answer» SOLUTION :Molar MASS of pure NaCl = `23+35.5=58.5"g mol"^(-1)` `% " of Cl in pure NaCl "=(35.5)/(58.5)xx100=60.6` Thus, 60.6 parts of Cl are PRESENT in 100 parts of pure NACl 45.5 parts of Cl will be present in pure NaCl `=(100)/(60.6)xx45.5="75 parts"` The remaining `25%` is impurity present in impure sample. HENCE, `%` of pure NaCl in impure sample = `75%`. |
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