1.

On charging lead storage cell. . .

Answer»

Pb of electrode utilize.
Solution becomes diluted
`H_(2)SO_(4)` of solution is utilized.
`PbO_(2)` is DEPOSITED on one electrode.

Solution :On charging of lead storage CELL, `PbO_(2)` is obtained at anode on oxidation REACTION.
`PbSO_(4(S))+2H_(2)O_((l))underset("Charging")overset("DC voltage") toPbO_(2(S))+SO_(4(aq))^(2-)+4H_((aq))^(+)+2e^(-)`
Where, (A), (B) and (C) is INDICATION of discharging reaction of storage cell.


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