| 1. |
On compairing the ratios a1/a2 , b1/b2, c1/c2 find out whether the following consistent or inconsistent 12x+20y=8, 3x-5y=3 |
Answer» Answér :Consistent Note:★ A linear equation is two variables represent a straight line . ★ The word consistent is USED for the system of equations which CONSISTS any solution . ★ The word inconsistent is used for the system of equations which doesn't consists any solution . ★ Solution of a system of equations : It refers to the possibile values of the variable which satisfy all the equations in the given system . ★ A pair of linear equations are said to be consistent if their graph ( Straight line ) either intersect or coincide each other . ★ A pair of linear equations are said to be inconsistent if their graph ( Straight line ) are PARALLEL . ★ If we consider equations of two straight line AX + by + c = 0 and a'x + b'y + c' = 0 , then ; • The lines are intersecting if a/a' ≠ b/b' . → In this case , unique solution is found . • The lines are coincident if a/a' = b/b' = c/c' . → In this case , infinitely many solutions are found . • The lines are parallel if a/a' = b/b' ≠ c/c' . → In this case , no solution is found . Solution :Here, The given linear equations are ; 12x + 20y = 8 3x - 5y = 3 The given equations can be REWRITTEN as ; 12x + 20y - 8 = 0 3x - 5y - 3 = 0 Clearly , we have ; a1 = 12 a2 = 3 b1 = 20 b2 = -5 c1 = -8 c2 = -3 Now , a1/a2 = 12/3 = 4 b1/b2 = 20/-5 = -4 c1/c2 = -8/-3 = 8/3 Clearly , a1/a2 ≠ b1/b2 Thus , The given equations has an unique solution . Hence ,The given equations are consistent . |
|