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On coolidge tube when 25 kV potential is applied current is obtained 2.2 mA. If the distance between the electrode is 1 m calculate (i) Heat produce at anode in cal/sec. (ii) no. of electron striking the anode per second (iii) Velocity of electron striking the anode (iv) Energy of electron |
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Answer» Solution :`(i) (5.5)/(4.2)"CAL"//s"" (ii) (11)/(8)xx10^(16)e` `(iii)9.4 xx 10^(7) m//s"" (iv) 25 KEV` |
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