On decomposition of `NH_(4)HS` , the following equilibrium is estabilished: `NH_(4) HS(s)hArrNH_(3)(g) + H_(2)S(g)` If the total pressure is P atm, then the equilibrium constant `K_(p)` is equal toA. P atmB. `P^(2) atm^(2)`C. `P^(2) // 4 atm^(2)`D. 2P atm

On decomposition of `NH_(4)HS` , the following equilibrium is estabili

1.	On decomposition of `NH_(4)HS` , the following equilibrium is estabilished: `NH_(4) HS(s)hArrNH_(3)(g) + H_(2)S(g)` If the total pressure is P atm, then the equilibrium constant `K_(p)` is equal toA. P atmB. `P^(2) atm^(2)`C. `P^(2) // 4 atm^(2)`D. 2P atm
Answer» Correct Answer - C `P_(NH_(3)) = P_(H_(2)S) = (P)/(2)` Hence `K_(p) = P_(NH_(3))xxP_(H_(2)S)` `=(P)/(2)xx(P)/(2) = (P^(2))/(4)`

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