On dissolving 3.24 g of sulphur in 40 g of sulphur in 40 g of benzene, – InterviewSolution

1.	On dissolving 3.24 g of sulphur in 40 g of sulphur in 40 g of benzene, boiling point of solution was higher than that of benzeneby 0.81 K. K_(b) value for benzene is "103.0 g mol"^(-1), calculate the molal elevation constant for benzene.
Answer» Solution :Calculate MOLECULAR MASS of the solute (sulphur). We get `M_(2)=253`. HENCE, no. of atoms present in one molecule = 253/32 = 8, i.e., the formula is `S_(8)`.

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