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On heating lead (II) nitrate gives a brown gas "A". The gas "A" on cooling changes to colourless solid "B". Solid "B" on heating with no changes to a blue solid 'C'. Identify 'A', 'B' and 'C' and also write reactions involved and draw the structures of 'B' and 'C'. |
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Answer» Solution :The gas A is `NO_2`. The reactions are explained as under : `2Pb(NO_3)_2 UNDERSET(673K) overset(Delta)to 2PbO + underset(" A(Brown colour)")(4NO_2) + O_2` `2NO_2 overset("On cooling ")to underset("(Colourless SOLID)")(N_2O_4)` `2NO+ underset(B)(N_2O_4) overset(250K)to underset("C (Brown colour solid )")(2N_2O_3)` STRUCTURE of B `(N_2O_4)` :
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