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On hydrolysis of salts of strong acid and strong base, the solution obtained is neutral.Justify your answer with a suitable example. |
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Answer» Solution :Let us consider the REACTION between `NaOH` and NITRIC acid to give sodium nitrate and water. `NaOH_((aq))+HNO_(3(aq)) to NaNO_(3(aq))+H_2O(I)` The salt `NaNO_3` completely dissociation in water to produce `Na^+ and NO_3^-` ions. `NaNO_(3(aq)) to NO_((aq))^(+)+NO_(3(aq))^-` Water dissociation to a small extent as `H_2O(I) hArr H_((aq))^(+)+OH_((aq))^-` Since `[H^+]=[OH^-]`,water is neutral `NO_3^-` ion is the conjugate base of the strong acid `HNO_3` and hence it has no tendency to react with `H^+` Similarity, `Na^+` is the conjugate acid of the strong base `NaOH` and it has no tendency to react with `OH^-` it means that there is no hydrolysis. In such cases `[H^+]=[OH^-] PH` is maintained and, THEREFORE, the solution is neutral . |
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