InterviewSolution
Saved Bookmarks
| 1. |
On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross section 2`mm^2`, the force required is [Y for steel `=2.2xx10^11(N)/(m^2)`]A. `1.1xx10^5N`B. `1.1xx10^4N`C. `1.1xx10^3N`D. `1.1xx10^2N` |
|
Answer» Correct Answer - D `Y=(Fl)/(Atrianglel)` or `F=(YAtrianglel)/(l)` or `F=(2.2xx10^11xx2xx10^-6xx0.5xx10^-3)/(2)=1.1xx10^2N` |
|