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On litre of 0.15 M Na_(2)SO_(3) aqueons solution is mixed with 500 mL of 0.2 M K_(2)Cr_(2)O_(7) aqueous solution in acid medium. What is the number of moles of K_(2) Cr_(2)O_(7) remaining in the solution after the reaction ? |
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Answer» 0.1 `M=(M_(1)V_(1)+M_(2) V_(2))/(V_(3))` `M=(0.15xx1+0.2xx0.5)/(1 cdot 5)` M=0.15 mol/L Remaining mole of `K_(2) Cr_(2)O_(7) =0.2-0.15` `=0.05` mol/L |
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