On mixing 1 mole of C_(6)H_(6) (P^(0) = 42 mm) and 2 mole of C_(7)H_(8 – InterviewSolution

1.	On mixing 1 mole of C_(6)H_(6) (P^(0) = 42 mm) and 2 mole of C_(7)H_(8) (P^(0) = 36 mm), one can conclude
Answer» total VAPOUR pressure of MIXTURE = 38 mm mole FRACTION of vapours of `C_(6)H_(6)` above liquid mixture `= (7)/(19)` positive deviation from RAOULT's law ideal solution of two Answer :A::B::D

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