1.

On passing 9.65 amperes of electricity for 1000 seconds, 2.0 grams of metal deposits . The molar of metal is

Answer»

40
20
2
10

Solution :`E=Zxx96,500`
`=(W)/(It) = 96,500 `
=`(2)/(9.65 XX 1,000) xx96,500 =20`


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