1.

On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of CuCl_(2) , all copper of the solution of CuCl_(2) solution was (Molar massof Cu = 63.5 , Faraday constant = 96500 C mol^(-1)).

Answer»

0.07 M
0.2 M
0.005 M
0.02 M

Solution :`Q = 1 XX 965 = 965` C
`Cu^(2+) + 2e^(-) to Cu`,
`2 xx 96500` C decompose `CuCl_(2) = 1 ` mole
`THEREFORE` 965 C decompose `CuCl_(2) = (1 xx 965)/(2 xx 96500) =(1)/(200)` mole
This was PRESENT in one litre of `CuCl_(2)` solution .
HENCE , strength = 0.005 M.


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