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On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of CuCl_(2), al copper of the solution was deposited at the cathode. Calculate the strength of CuCl_(2)solution (Molar mass of Cu=63.5, faraday constant=96500 C mol^(-1)) |
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Answer» SOLUTION :`Q=Ixxt=1xx965=965C` `Cu^(2+)+2E^(-)toCu` `therefore965C` decompose `CuCl_(2)=(1)/(2xx96500)xx965=(1)/(200)`MOLE=0.005 mole This was PRESENT in 1 L of `CuCl_(2)` solution, Hence, strength=0.005M. |
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