1.

On passing a current of 1.0 ampere for 16 min and 5 seconds through 1 L solution of CuCl_(2), all copper of the solution was deposited at cathode. The molarity of CuCl_2 solution was

Answer»

0.1M
0.01 M
0.005 M
0.2 M

SOLUTION :`Cu^(2+) + 2 E rarr Cu`
`2 xx 96500 C -= 1 mol Cu=1 mol CuCl_(2)`
`Q =1 xx t =1 xx (60 xx 16 +5) = 965 C`
` therefore965 ` C will deposit `-= (965)/(2 xx 96500)=(1)/(2000)` mole `CuCl_(2)`
`therefore` MOLARITY of `CuCl_(2)` solution `= (1)/(200)` mol `L^(-1)` = 0.005 M


Discussion

No Comment Found

Related InterviewSolutions