1.

On passing SO_(2) gas through an acidified solution of K_(2)Cr_(2)O_(7)

Answer»

The Solution GETS decolourised
The solution BECOMES blue
`SO_(2)` is REDUCED
Green `Cr_(2)(SO_(4))_(3)` is obtained

Solution :`K_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4) to Cr_(2)(SO_(4))_(3)+H_(2)O`


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