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On Q, the set of all rational numbers, a binary operation * is definedby `a*b=(a b)/5`for all `a , b in Qdot`Find the identity element for * in Q. Also, prove that every non-zeroelement of Q is invertible. |
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Answer» Here, `a**b = (ab)/5`. An identity element `e` in a relation is an element such that `a**e = e**a = a.` So, in the given relation, `a**e = (ae)/5 = a => ae = 5a => e = 5` So, identity element is `5` for the given relation. Now, for any element `x in Q`, If `a**x = e`, then `x` is inverse of `a`. Here, `a**x = 5 => (ax)/5 = 5` `x = 25/a` So, inverse of given relation is `25/a` where `a in Q`. So, `Q` is invertible for every non-zero element. |
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