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On screen there are two bright points at a distance I mm. These points are observed by the person whose eye is having diameter 3 mm from which maximum distance this person can observe them resolved ? |
Answer» Solution : Resolution power `=(1.22 LAMBDA)/(d)` and `sin theta~~=(y)/(D)` `:.(y)/(D)=(1.22 lambda)/(d)` `:. D=(yd)/(1.22lambda)=(10^(-3)xx3xx10^(-3))/(1.22xx5xx10^(-7))=(30)/(6.1)=5 m` |
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