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On shining light of wavelength 6.2xx10^(-6) m on a metal surface photo-electrons are emitted. The work function of the metal is 0.1 eV. Find the kinetic energy of a photo-electron (in eV) |
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Answer» 0.1 Energy of the incident photon , `E=hupsilon=(hc)/lambda` `E=((6.6xx10^(-34))(3xx10^8))/(6.2xx10^(-6))`J `=(6.6xx3xx10^(-26))/((6.2xx10^(-6))(1.6xx10^(-19)))` eV=0.2 eV As `E=K+phi_0 , K=E- phi_0`=0.2 eV - 0.1 eV =0.1 eV |
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