1.

On strong heating 4 gm of a solid compound produced 528 ml of a diatomic gas (A_(2)) at NTP condittion and 2.68 gm of solid residue. The atomic mass of element A is -

Answer»

56 gm
112 gm
28 gm
14 gm

Solution :`X overset(DELTA)(rarr) A_(2) (g) + Y`
`4 gm "" 2.68 gm`
`A_(2) (g) = 4 - 2.68 = 1.32gm`
`n_(A_(2)) (g) = (V ("gas") NTP "in litre")/(22.4) = (w ("gas") H_(2))/(M.Wt.A_(2))`
`n_(A_(2)) (g) = (528)/(22400) = (1.32)/(M.Wt.A_(2))`
`M.Wt.A_(2) = 56 gm = 2 xx` Atomic mass of A
Atomic mass of `A = 28 gm`


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