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On the basis of Eq,(6.4g) find the number of free electrons in a metal at T=0 as a function of de Broglie wavelengths. |
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Answer» Solution :Using the formula of the previous section `dn(v)=(m^(3))/(PI^(2)ħ^(3))v^(2)dv` We put `MV=(2piħ)/(LAMBDA)`, where `lambda=` Broglie WAVELENGTH `mdv(2piħ)/(lambda^(2))d lambda` Taking account of the fact that `lambda` DECREASES when `v` increase we write `db(lambda)= -dn(v)=((2pi)^(3)dlambda)/(pi^(2)lambda^(4)).=(8pi)/(lambda^(4))d lambda` |
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