1.

On the basis of following equations the heat of dimerisation of NO_(2) will be(i)N_(2)+2O_(2)rarr2NO_(2) ""DeltaH=67.9 kJ(ii)N_(2)+2O_(2)rarrN_(2)O_(4) ""DeltaH=09.3 kJ

Answer»

`+77.2 kJ`
`-77.2 kJ`
`-58.6 kJ`
`+58.6 kJ`

Solution :Our desirable EQUATION is
`2NO_(2)rarrN_(2)O_(4)"...(iii)"`
Given
`2NO_(2)rarrN_(2)+2O_(2)DeltaH=-67.9 kJ "...(i)"`
`N_(2)O_(4)rarrN_(2)+2O_(2)DeltaH=-09.3 kJ "...(ii)"`
On substracting equation (ii) from (i) we will GET equation (iii)
`2NO_(2)-N_(2)O_(4)rarr0`
`2NO_(2)rarrN_(2)O_(4)"....(iii)"`
So Heat of dimerisation of `NO_(2)=-67.9-(-09.3)kJ=-67.9+9.3 =-58.6 kJ`


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