InterviewSolution
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InterviewSolution
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On the basis of the following thermochemical data `(Delta f G^(@)H_((aq))^(+)=0)` `H_(2)O(l) rarr H^(+)(aq)+OH^(-)(aq), DeltaH=57.32 kJ` `H_(2)(g)+1/2 O_(2)(g) rarr H_(2)O(l), DeltaH=-286.20 kJ` The value of enthalpy of formation of `OH^(-)` ion at `25^(@)C` is -A. `-228.88 kJ`B. `+ 228.88 kJ`C. `-343.52 kJ`D. `-22.88 kJ` |
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Answer» Correct Answer - A `H_(2)O(l) rarr H^(+) (aq) +OH^(-)(aq), DeltaH=57.32 kJ" "`....(i) `H_(2)(g) +1/2 O_(2)(g) rarr H_(2)O(l), DeltaH=-286.20 KJ" "`.....(ii) For the reaction `H_(2)(g)+1/2 O_(2) (g) rarr H^(+)(aq) +OH^(-)(aq)" "DeltaH=?` By adding equation (i) and (ii) `H_(2)(g)+1/2 O_(2)(g) rarr H^(+) (aq) +OH^(-) (aq)" "DeltaH=57.32 kJ -286.20 kJ` `DeltaH=-280.88" kJ/mol"` |
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