1.

On the basis of the given equivalent conductivity lamda_(oo)(NH_(4)Cl)=130 lamda_(oo)(OH^(-))=174 lamda_(oo)(Cl^(-))=66 The value of lamda_(oo)(NH_(4)OH) will be

Answer»

304
238
108
64

Solution :`NH_(4)CL+OH^(-)toNH_(4)OH^(-)+Cl^(-)`
`130+174tox+66`
`304tox+66`
`304-66tox`
`x=238`


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