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On the basis of your understanding of the following paragraphand the related studied concepts. An equipotential surface is a surface with a constant value of electric potential at all points on the surface. The component of electric field parallel to an equipotential surface is zero, as the potential does not change in this direction. Thus, the electric field is perpendicular to the equipotential surface at each point of the surface. Further, say the direction of electric field electrical potential gradually fall with distance. Four equipotential surfaces are shown in the adjoining figure. Find the magnitude and direaction of the electric field. |
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Answer» Solution :As SHOWN in figure for any two consecutive equipo tential surfaces `DeltaV = 10V` and normal distance between then `Delta r = Deltax sin 30^@ = 10 sin 30^@ cm = 5 cm = 0.05 m` `:. absvecE= (DeltaV)/(DELTAR) = (10V)/(0.05m) = 200 V m^(-1)` Direction of `VECE` is at right angle to an equipotential SURFACE along the direction of decreasing potential, hence `vecE` is directed at an angle of `102^@` from x-axis. 
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