1.

On the electrolysis of aqueous solution of sodium sulphate, on cathode we get

Answer»

Na
`H_2`
`SO_2`
SO_3`

SOLUTION :Water is reduced at the cathode and oxidized at the anode
INSTEAD of `Na^(+) and SO_(4)^(2-)`
Cathode: `2H_(2)O+2E^(-)toH_(2)+2OH^(-)`
Anode: `H_(2)Oto2H^(+)+(1)/(2)O_(2)+2e^(-)`.


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