1.

On treatmentof [Ni(NH_(3))_(4)]^(+2) with conc.HC/ two compounds I and II having the same formula [Ni(NH_(3))_(2)Cl_(2)] are obtained, I can be converted into II by boiling with dil.HCI. A solution of I reacts with oxalic acid to form [Ni(NH_(3))_(2)(C_(2)O_(4))] where as II does not react. Point out the correct statement from the following

Answer»

I CIS, II TRANS, both tetrahedral
I cis, II trans both square planar
I trans, II cis, both tetrahedral
I trans, Il cis both square planar

SOLUTION :Cis-form REACTS with `C_(2)O_(4)^(2-)` trans-form does not react with `C_(2)O_(4)^(2-)`


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