Saved Bookmarks
| 1. |
One among the langthanides ,Ce(III), can be easily oxidized to Ce(IV)(At. No. of Ce= 58) . Explain why ? Or Of the lanthanides, cerium (At. No. 58) forms a tetrapositive ion, Ce^94+) in aqueous solution. Why? |
| Answer» Solution :CE(III) having the configuration `4f^(1) 5D^(-) 6S^(0)` can EASILY lose an electron to acquire the configuration `4f^(0)` and form Ce(IV) . In fact , this is theonly `( + IV)` lanthanide which exists in solution. | |