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InterviewSolution
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One Ball Is Picked Up Randomly From A Bag Containing 8 Yellow, 7 Blue And 6 Black Balls. What Is The Probability That It Is Neither Yellow Nor Black? |
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Answer» TOTAL number of balls, n(S) = 8 + 7 + 6 = 21 n(E) = Number of ways in which a ball can be SELECTED which is neither yellow nor black = 7 (∵ there are only 7 balls which are neither yellow nor black) P(E) = n(E)/n(S)=7/21=1/3. Total number of balls, n(S) = 8 + 7 + 6 = 21 n(E) = Number of ways in which a ball can be selected which is neither yellow nor black = 7 (∵ there are only 7 balls which are neither yellow nor black) P(E) = n(E)/n(S)=7/21=1/3. |
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