1.

One capacitor with plate area A is being charged up. At a particular instant when charging current is I, what will be displacement current through a planar loop of area (A)/(2), imagined between the plates and parallel to them ?

Answer»

I
`(I)/(2)`
`(I)/(4)`
`(I)/(8)`

Solution :For a capacitor being CHARGED, conduction current density at any point inside the plate and displacement current density at any point between the plates are always same. HENCE,
`(I)/(A)=(i_(d))/(((A)/(2)))`
`therefore I=2i_(d)`
`therefore i_(d)=(I)/(2)`


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