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One coil with 40 turns and 4 "cm"^2 area of cross-section is kept perpendicular to one uniform magnetic field of flux density B. When this loop is pulled out of magnetic field suddenly, 2 xx 10^(-4) C electric charge flows through it. If resistance of this coil is 80Omega then B= ____ "Wb/m"^2.

Answer»

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Solution :`Q=(DELTAPHI)/R`
`=(NAB)/R`
`therefore B=(QR)/(NA)`
`=(2xx10^(-4)xx80)/(40xx4xx10^(-4))`
`therefore B=1 "Wb/m"^2`


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