1.

One coulomb of charge passes through a solution of AgNO_(3) and CuSO_(4) connected in series and the concentration of the two solutions is in the ratio 1:2. The ratio by weight of Ag and Cu deposited on Pt electrode is :

Answer»

`107.9:63.54`
`54:31.77`
`107.9:31.77`
`54:63.54`

Solution :(C ) According to Faraday's second LAW of ELECTROLYSIS
`("Weight of AG deposited")/("Equivalent weight of Ag")=("Weight of Cu deposited")/("Equivalent weight of Cu")`
`(W_(Ag))/(W_(cu))=(E_(Ag))/(E_(Cu))=(107 g)/((163.54)//2)=(107.9)/(31.77)`

or `107.9:31.77`


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