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One end of a cylindrical rod is grounded to a hemispherical surface of radius R = 30 mm. The refractive index of rod is 1.5. Find the position of the image placed on the axis of the rod at 10 cm from the pole. |
Answer» Solution : Refraction OCCURS from air to glass at CONVEX spherical surface APB. `mu_(1)=1,""mu_(2)=1.5` `u=-10cm,""R=30mm=3cm` We have, `(mu_(2))/(v)-(mu_(1))/(u)=(mu_(2)-mu_(1))/(R )` `rArr""(1.5)/(v)+(1)/(10)=(1.5-1)/(3)=(0.5)/(3)` `rArr""(1.5)/(v)=(0.5)/(3)-(1)/(10)` `""=(5-3)/(30)=(2)/(30)=(1)/(15)` `rArr""v=15xx1.5=22.5cm` As v is positive, so a real image is formed at 22.5 cm from END P of the rod. |
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