InterviewSolution
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InterviewSolution
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One end of a spring is rigidly fixed. A block attached to the free end of the spring is pulled through a distance `x_(0)`. On releasing the block, its amplitude of motion cannot exceed `+-x_(0)`. Why? |
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Answer» When the spring is stretched by `x_(0)` its P.E. `=(1)/(2)kx_(0)^(2)` where k is spring constant. At `xgtx_(0)`. PE will be greater than `(1)/(2)kx_(0)^(2).` Therefore , its `KE=((1)/(2)kx_(0)^(2)-(1)/(2)kx^(2))` would be negative, which is not possible. Therefore, amplitude of motino cannot exceed `+-x_(0)`. |
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