InterviewSolution
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InterviewSolution
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One end of a taut string of length `3m` along the x-axis is fixed at `x = 0`. The speed of the waves in the string is `100ms^(-1)`. The other end of the string is vibrating in the y-direction so that stationary waves are set up in the string. The possible wavelength`(s)` of these sationary waves is (are)A. (a) `y(t) = A sin(pix)/(6)cos(50pit)/(3)`B. (b) `y(t) = A sin(pix)/(3)cos(100pit)/(3)`C. ( c ) `y(t) = A sin(5pix)/(6)cos(250pit)/(3)`D. (d) `y(t) = A sin(5pix)/(2)cos 250pit` |
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Answer» Correct Answer - A::C::D (a,c,d) Clearly in the given situation a displacement node is present at `x = 0` and `a` displacement antitode is present at `x = 3m`. The velocity `v = (omega)/(k) = 100ms^(-1)`. `a , c and d` are the coerrct option which satisfy the above conditions. |
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