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One faraday of electricity deposits one mol of Na from the molten salt but (1)/(3) mol of Al from an aluminium salt. Why? |
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Answer» Solution :The reactions at cathode for the deposit of Na and AL are `Na^(+)+e^(-)toNa and Al^(3+)+3e^(-)toAl` Thus, 1 FARADAY DEPOSITS 1 MOL of Na whereas 3 faradays are required for DEPOSITING one mol of Al. |
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