1.

One Faraday of electricity is passed through molten Al_(2)O_(3), aqueous solution of CuSO_(4)and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of AI, Cu and Na deposited at the respective cathode is

Answer»

`2:3:6`
`6:2:3`
`6:3:2`
`1:2:3`

Solution :The charge carried by 1 mole of electrons is ONE faraday. Thus for a reaction
`M^(n+) +nc ^(-) to M`
`nF=1` mole of M
`{:(Al^(3+)+3e^(-) to Al),(3F """1mole"),(IF"""1/3mole"):} `
`{:(Cu^(2+) +2C^(-) to Cu),(2F """1mole"),(IF """1mole"):}`
`{:(Na^(+)+E ^(-) to Na),(IF """mole"):}`
The mole ration of Al, Cu and Na deposited at eh respectivecat ODE is `1/3. 1/2: 1 sigma 2:3:6`


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