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One Faraday of electricity is passed through molten Al_(2)O_(3), aqueous solution of CuSO_(4) and molten NaCl taken in three different electrolytic cells connected in series . The mole ratio of Al , Cu and Na deposited at the respective cathode is : |
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Answer» `2: 3: 6` `Cu^(2+)+underset(1F)underset(2F)2E^(-) to underset(1//2mol)underset(1mol)(Cu)` `Na^(+)+underset(1F)e^(-) to underset(1mol)(Na)` Mole RATIO of Al, Cu and Nadeposited at the respective CATHODES is : `1//3 : 1//2 : 1//1 "or"2:3:6` |
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