One gram mole of graphite and diamond were burnt to form `CO_(2)` gas: `C_(("graphite"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-399.5kJ` `C_(("diamond"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-395.4 kJ`A. graphite is more stable than diamondB. diamond is more stable than graphiteC. graphite has greater affinity with oxygenD. diamond has greater affinity with oxygen.

One gram mole of graphite and diamond were burnt to form `CO_(2)` gas:

1.	One gram mole of graphite and diamond were burnt to form `CO_(2)` gas: `C_(("graphite"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-399.5kJ` `C_(("diamond"))+O_(2)(g)toCO_(2)(g)," "DeltaH^(@)=-395.4 kJ`A. graphite is more stable than diamondB. diamond is more stable than graphiteC. graphite has greater affinity with oxygenD. diamond has greater affinity with oxygen.
Answer» Correct Answer - A Thermal stability of one isotope is directly proportional to the heat of combustion.

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